Total cost price=36×45+24×48=2772/-
Average cost price per kg = 2772/60 = Rs. 46.2
S.P=Rs 55.44 per kg( @20% profit).
Let ‘l’ be the length, ‘b’ be the breadth of the rectangle.
Length of the rectangle =Side of the square of area 729m2
∴ Length of the rectangle =27m. A.T.Q. l-b=6
⇒ b = l - 6 = 21m ⇒ l = 27m
Perimeter of the rectangle = 2 (l + b) = 2 (27 + 21) = 96m
Question 4. Raghuvir Purchased 10 Calculators And 16 Watches For Rs. 56,100/- And Sold Them So As To Earn An Overall Profit Of 20%. At What Total Price Should He Sell 15 Calculators And 24 Watches Together So As To Earn The Same Percent Profit?
CP of 10 calculators , 16 watches =Rs.56100/-
CP of 15 calculators, 24 watches=1.5×56100=84150/-
∴S.P. of 15 calculators, 24 watches =1.2×84150 = Rs. 100,980/-
Question 5. Some Chocolates Were Distributed Among 4 Friends A, B, C And D Such That Respective Ratio Of Chocolates Received By A To Chocolates Received By C Was 7:9. B Received 29 More Chocolates Than A And D Received 33 More Chocolates Than C. If B Received 15 More Chocolates Than C, How Many Chocolates Did D Receive?
A=7x, C=9x, B=7x+29, D=9x+33
A.T.Q. 29 + 7x =15+9x
⇒ x = 7
∴ D received 96 chocolates
Question 6. Abhijit Invested An Amount With Company X For Two Years @ Simple Interest Rate 15 P.c.p.a. The Entire Amount Obtained From Company X After Two Years He Invested With Company Y @ Compound Interest Rate 12 P.c.p.a For Two Years. If The Amount Finally Received By Him Was Rs. 81,536. Find The Money Invested By Abhijit In Company X?
Let ‘y’ be the invested amount
On Solving y=Rs.50,000/-
Let the number of so be ‘3x’ and the number of lilies be 2x
Average number of roses and lilies = (3x + 2x)/2 = 2.5x
2.5x = 180, x = 72
Number of lilies = 2x = 144.
Let the total work = 1
i.e. A + B+C =1 A and B will complete 7/11 of work.
Remaining work => C = 1- (7/11) = 4/11
Therefore salary received by C = (4/11)*550 = Rs. 200.
Question 9. One Bottle Is Half-full Of Oil And Another Bottle With Twice The Capacity Is One Quarter Full Of Oil. If Water Is Added So That Both The Bottles Are Full And The Contents Of Both Are Then Poured Into A Third Bottle That Is Empty And Large Enough To Hold The Contents Of Both, What Fractions Of The Contents In The Third Bottle Is Oil?
Capacity of 1st bottle =100 litres
Quantity of Oil=50 litres & Water=50 litres
Capacity 2nd bottle =200 litres
Quantity of Oil=50 litres & Water=150 litres
Capacity of 3rd bottle = 300 litres
Quantity of Oil=100 litres & Water = 200 litres
The fraction of the oil contents in the third bottle is = 100 / (100+200) = 1/3.
Question 10. An Investor Purchased Shares Of Stock At A Certain Price. If The Stock Increased In Price Rs 0.25 Per Share And The Total Increase For The X Shares Was Rs 12.50, How Many Shares Of Stock Had Been Purchased?
Let 1 Rs.
be the cost of each share and x is the no of shares c.p. = x Rs.
for x shares If 0.25 Rs.
is increased in each share Then (1+.25)
x = 12.50+x 1.25x = 12.50+x 0.25x =12.50 x = 12.50/0.25
=> x =50 Therefore number of shares=50.
Number of days worked in a week =1+1/3+2/3+1/8+3/4 = (24 +8 + 16 + 3+ 18)/ 24 = 69/ 24 =23/8 days
Total amount paid = 23/8 * 20= 57.50 Rs.
Question 12. Don And His Wife Each Receive An 8 Percent Annual Raise. If Don Receives A Raise Rs.800 And His Wife Receives A Raise Of Rs. 840, What Is The Difference Between Their Annual Incomes After Their Raises?
8% is 800 hence 100% = 10,000 for Don.
8% is 840 hence 100% = 10,500 for his wife.
After raise Don salary = 10,000+800 = 10,800 and his wife salary is 10,500+840.
Difference is 11,840-10,800 = 540.
Question 13. It Takes 6 Technicians 10 Hours To Build And Program A New Server From Direct Computer, With Each Working At The Same Rate. If Six Technicians Start To Build The Server At 11:00 Am, And One Technician Per Hour Is Added Beginning At 5:00 Pm, At What Time Will The Server Be Complete?
Total time required to complete job is 6 * 10 = 60 hours Work completed between 11am to 5pm by 6 technician = (6 * 6) = 36 hours
So remaining work = (60 - 36) = 24 hours Remaining work between 5pm to 6pm = 24 -7 = 17 hours.
Similarly work completed between 6pm to 7 pm = 17 – 8 = 9 hours,
which is completed in next one hour i.e. Job is complete at 8.00PM.
We know that
Selling price = cost price + profit
Cost Price = 12.60
Profit = 10% of CP = (10 / 100) * 12.60 = 126 /100 Profit = 1.26
Selling Price = CP + Profit = 12.60 + 1.26 Selling Price = 13.86.
Selling price = cost price + profit
Cost price = 225 + 15 = 240
i.e. 240 + X * 240 * 1/100 = 300
240 + 24X/ 10 = 300
(taking LCM) 2400 + 24X = 3000
24 X = 3000 - 2400
24X = 600
X = 600/ 24
X = 25.
If A takes x days to do a work then B takes 2x days to do the same work
= > 1/x+1/2x = 1/18
= > 3/2x = 1/18
= > x = 27 days.
Hence, A alone can finish the work in 27 days.
Let the length of the train be x meters Then,
the train covers x meters in 8 seconds and (x + 180) meters in 20 seconds.
Therefore x/8 = (x+180)/20
<=> 20x = 8(x+180)
<=> x = 120
Therefore Length of the train = 120m
Speed of the train = 120/8 m/sec = 15 m/sec =15 * 18/5 kmph = 54kmph.
Question 18. Pipe A Can Fill A Tank In 20 Minutes And Pipe B In 30 Minutes Respectively. Pipe C Can Empty The Same In 40 Minutes. If All The Three Pipes Are Opened Together, Find The Time Taken To Fill The Tank?
Net part filled in 1 hour = ( 1/20 – 1/30 – 1/40) = 7 / 120
Therefore tank will be filled in = 120/7 = 17 1/7 minutes.
The simple interest formula is Interest = Principal × Rate × Time
I = P×R×T Where: 'Interest' is the total amount of interest paid, 'Principal' is the amount lent or borrowed, 'Rate' is the percentage of the principal charged as interest each year.
The rate is expressed as a decimal fraction, so percentages must be divided by 100.
'Time' is the time in years of the loan.
S.I = P×R×T S.I. = Rs. 4000 * 8% * 3 months
S.I. = 4000* 8 /100 * 3/12 S.I. = 80.
Total number of shoes=6 + 4=10;
let S be the sample space.
Then, n(s) = Number of ways of drawing 2 shoes out of 10 =10C2 =(10 x 9)/(2 x 1) =45
Let E = Event of drawing 2 shoes which are red.
Therefore n(E) = Number of ways of drawing 2 red shoes out of 6 shoes.= 6C2 =(6 x 5)/(2 x 1) =15 P(E) = n(E)/n(S) = 1/3.
Case 1: Initial quantity of Water = 15 litres
Quantity of Alcohol = 20% = (20/100) * 15 = 3 litres
Case 2: Quantity of Water after adding 5 litres of water = 15 + 5 = 20 litres
There of the % of alcohol in water = (3 /20) * 100 = 15%.
2x / y Explanation:
Let’s take `z` as the original number of coins.
We know that 10x + z = (5y + 1) z
i.e.10x + z = 5yz + z 10x/5y = z z = 2x/y.
Rate downstream= 20 /4 = 5 kmph
Rate upstream= 18 / 6 = 3 kmph
Speed in still water = 1/2 (5 + 3) = 4 kmph.
Area covered by goat A = πr2
here we divide by 4 because rope is tied at the corner of the plot and only 1/4 part,
the goat can graze Where length of rope r = 7 m.
A = πr2 / 4 A = 1/4(area of circle)
A = ¼ [(22/7)*7*7] A = 38.5
Question 25. Vivek Travelled 1200km By Air Which Formed 2/5 Of His Trip. One Third Of The Whole Trip, He Travelled By Car And The Rest Of The Journey He Performed By Train. The Distance Travelled By Train Was?
Let the total trip be X km.
We know that 2X/5 = 1200 km
X = 1200*5/2 = 3000 km
Distance travelled by car = 1/3*3000 = 1000km
Journey by train = [3000-(1200+1000)] = 800km.
Sony India Aptitude Related Interview Questions
|Aptitude Interview Questions||Wipro Aptitude Interview Questions|
|ABB Group Aptitude Interview Questions||VMware Aptitude Interview Questions|
|Value Labs Aptitude Interview Questions||Abaxis Aptitude Interview Questions|
|Yahoo Aptitude Interview Questions||SAP Aptitude Interview Questions|
|Oracle Aptitude Interview Questions||BHEL Aptitude Interview Questions|
Sony India Aptitude Related Practice Tests
|Aptitude Practice Tests|
All rights reserved © 2020 Wisdom IT Services India Pvt. Ltd
Wisdomjobs.com is one of the best job search sites in India.