Question 1. 156.25 × 12.4 + 1.8 × 52.5 = ? – 175.85
Answer :
156.25×12.4+1.8×52.5=?-175.85
1937.5+94.5=?-175.85
2032=?-175.85
?=2207.85
Answer :
Total cost price=36×45+24×48=2772/-
Average cost price per kg = 2772/60 = Rs. 46.2
S.P=Rs 55.44 per kg( @20% profit).
Answer :
Let ‘l’ be the length, ‘b’ be the breadth of the rectangle.
Length of the rectangle =Side of the square of area 729m2
∴ Length of the rectangle =27m. A.T.Q. l-b=6
⇒ b = l - 6 = 21m ⇒ l = 27m
Perimeter of the rectangle = 2 (l + b) = 2 (27 + 21) = 96m
Answer :
CP of 10 calculators , 16 watches =Rs.56100/-
CP of 15 calculators, 24 watches=1.5×56100=84150/-
Profit=20%
∴S.P. of 15 calculators, 24 watches =1.2×84150 = Rs. 100,980/-
Answer :
A=7x, C=9x, B=7x+29, D=9x+33
A.T.Q. 29 + 7x =15+9x
⇒ x = 7
∴ D received 96 chocolates
Answer :
Let ‘y’ be the invested amount
A.T.Q.
1.3y(1.12)2=81536
On Solving y=Rs.50,000/-
Answer :
Let the number of so be ‘3x’ and the number of lilies be 2x
Average number of roses and lilies = (3x + 2x)/2 = 2.5x
A.T.Q
2.5x = 180, x = 72
Number of lilies = 2x = 144.
Answer :
Let the total work = 1
i.e. A + B+C =1 A and B will complete 7/11 of work.
Remaining work => C = 1- (7/11) = 4/11
Therefore salary received by C = (4/11)*550 = Rs. 200.
Answer :
Capacity of 1st bottle =100 litres
Quantity of Oil=50 litres & Water=50 litres
Capacity 2nd bottle =200 litres
Quantity of Oil=50 litres & Water=150 litres
Capacity of 3rd bottle = 300 litres
Quantity of Oil=100 litres & Water = 200 litres
The fraction of the oil contents in the third bottle is = 100 / (100+200) = 1/3.
Answer :
Let 1 Rs.
be the cost of each share and x is the no of shares c.p. = x Rs.
for x shares If 0.25 Rs.
is increased in each share Then (1+.25)
x = 12.50+x 1.25x = 12.50+x 0.25x =12.50 x = 12.50/0.25
=> x =50 Therefore number of shares=50.
Answer :
Number of days worked in a week =1+1/3+2/3+1/8+3/4 = (24 +8 + 16 + 3+ 18)/ 24 = 69/ 24 =23/8 days
Total amount paid = 23/8 * 20= 57.50 Rs.
Answer :
8% is 800 hence 100% = 10,000 for Don.
8% is 840 hence 100% = 10,500 for his wife.
After raise Don salary = 10,000+800 = 10,800 and his wife salary is 10,500+840.
Difference is 11,840-10,800 = 540.
Answer :
Total time required to complete job is 6 * 10 = 60 hours Work completed between 11am to 5pm by 6 technician = (6 * 6) = 36 hours
So remaining work = (60 - 36) = 24 hours Remaining work between 5pm to 6pm = 24 -7 = 17 hours.
Similarly work completed between 6pm to 7 pm = 17 – 8 = 9 hours,
which is completed in next one hour i.e. Job is complete at 8.00PM.
Answer :
We know that
Selling price = cost price + profit
Cost Price = 12.60
Profit = 10% of CP = (10 / 100) * 12.60 = 126 /100 Profit = 1.26
Selling Price = CP + Profit = 12.60 + 1.26 Selling Price = 13.86.
Answer :
Selling price = cost price + profit
Cost price = 225 + 15 = 240
i.e. 240 + X * 240 * 1/100 = 300
240 + 24X/ 10 = 300
(taking LCM) 2400 + 24X = 3000
24 X = 3000 - 2400
24X = 600
X = 600/ 24
X = 25.
Answer :
If A takes x days to do a work then B takes 2x days to do the same work
= > 1/x+1/2x = 1/18
= > 3/2x = 1/18
= > x = 27 days.
Hence, A alone can finish the work in 27 days.
Answer :
Let the length of the train be x meters Then,
the train covers x meters in 8 seconds and (x + 180) meters in 20 seconds.
Therefore x/8 = (x+180)/20
<=> 20x = 8(x+180)
<=> x = 120
Therefore Length of the train = 120m
Speed of the train = 120/8 m/sec = 15 m/sec =15 * 18/5 kmph = 54kmph.
Answer :
Net part filled in 1 hour = ( 1/20 – 1/30 – 1/40) = 7 / 120
Therefore tank will be filled in = 120/7 = 17 1/7 minutes.
Answer :
The simple interest formula is Interest = Principal × Rate × Time
I = P×R×T Where: 'Interest' is the total amount of interest paid, 'Principal' is the amount lent or borrowed, 'Rate' is the percentage of the principal charged as interest each year.
The rate is expressed as a decimal fraction, so percentages must be divided by 100.
'Time' is the time in years of the loan.
S.I = P×R×T S.I. = Rs. 4000 * 8% * 3 months
S.I. = 4000* 8 /100 * 3/12 S.I. = 80.
Answer :
Total number of shoes=6 + 4=10;
let S be the sample space.
Then, n(s) = Number of ways of drawing 2 shoes out of 10 =10C2 =(10 x 9)/(2 x 1) =45
Let E = Event of drawing 2 shoes which are red.
Therefore n(E) = Number of ways of drawing 2 red shoes out of 6 shoes.= 6C2 =(6 x 5)/(2 x 1) =15 P(E) = n(E)/n(S) = 1/3.
Answer :
Case 1: Initial quantity of Water = 15 litres
Quantity of Alcohol = 20% = (20/100) * 15 = 3 litres
Case 2: Quantity of Water after adding 5 litres of water = 15 + 5 = 20 litres
There of the % of alcohol in water = (3 /20) * 100 = 15%.
Answer :
2x / y Explanation:
Let’s take `z` as the original number of coins.
We know that 10x + z = (5y + 1) z
i.e.10x + z = 5yz + z 10x/5y = z z = 2x/y.
Answer :
Rate downstream= 20 /4 = 5 kmph
Rate upstream= 18 / 6 = 3 kmph
Speed in still water = 1/2 (5 + 3) = 4 kmph.
Answer :
Area covered by goat A = πr2
here we divide by 4 because rope is tied at the corner of the plot and only 1/4 part,
the goat can graze Where length of rope r = 7 m.
A = πr2 / 4 A = 1/4(area of circle)
A = ¼ [(22/7)*7*7] A = 38.5
Answer :
Let the total trip be X km.
We know that 2X/5 = 1200 km
X = 1200*5/2 = 3000 km
Distance travelled by car = 1/3*3000 = 1000km
Journey by train = [3000-(1200+1000)] = 800km.
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