Question 1. 12.5 + 10 1/4 Of 100 ÷ 10% Of 10 = ?
Answer :
12.5 + 10 1/4 of 100 ÷ 10% of 10
= 12.5 + 41/4 of 100 ÷ 10/100 of 10
= 12.5 + 41(25) ÷ 1 = 12.5 + 1025 = 1037.5.
Question 2. 66% Of 33.33% Of 66.66% Of ? = 30
Answer :
16.66% of 33.33% of 66.66% of x = 30
= 1/6 of 1/3 of 2/3 of x = 30
=> (30 * 6 * 3 * 3)/2 => x = 810
Answer :
Speed = 54 * 5/18 = 15 m/sec.
Length of the train = 15 * 20 = 300 m.
Let the length of the platform be x m . Then,
(x + 300)/36 = 15 => x = 240 m.
Answer :
Speed = 300/18 = 50/3 m/sec.
Let the length of the platform be x meters.
Then, (x + 300)/39 = 50/3
3x + 900 = 1950 => x = 350 m.
Question 5. A Train Speeds Past A Pole In 15 Sec And A Platform 100 M Long In 25 Sec, Its Length Is?
Answer :
Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 15 => y = x/15
(x + 100)/25 = x/15 => x = 150 m.
Answer :
Let the length of the train be x m and its speed be y m/sec.
Then, x/y = 8 => x = 8y
(x + 264)/20 = y
y = 22
Speed = 22 m/sec = 22 * 18/5 = 79.2 km/hr.
Answer :
Speed of train relative to man = 63 - 3 = 60 km/hr.
= 60 * 5/18 = 50/3 m/sec.
Time taken to pass the man = 500 * 3/50 = 30 sec.
Answer :
Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 * 5/18 = 10 m/sec.
Distance to be covered = 240 + 120 = 360 m.
Time taken = 360/10 = 36 sec.
Answer :
Speed of train relative to man = 60 + 6 = 66 km/hr.
= 66 * 5/18 = 55/3 m/sec.
Time taken to pass the men = 110 * 3/55 = 6 sec.
Answer :
Relative speed = 60 + 40 = 100 km/hr.
= 100 * 5/18 = 250/9 m/sec.
Distance covered in crossing each other = 140 + 160 = 300 m.
Required time = 300 * 9/250 = 54/5 = 10.8 sec.
Answer :
Relative speed = 60 + 90 = 150 km/hr.
= 150 * 5/18 = 125/3 m/sec.
Distance covered = 1.10 + 0.9 = 2 km = 2000 m.
Required time = 2000 * 3/125 = 48 sec.
Answer :
Speed of the train relative to man = 125/10 = 25/2 m/sec.
= 25/2 * 18/5 = 45 km/hr
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 => x = 50 km/hr.
Answer :
A invests Rs.8000 for 18 months, but B invests Rs.8000 for the first 4 months and then withdraws Rs.4000.
So, the investment of B for remaining 14 months is Rs.4000 only.
A : B
8000*18 : (8000*4) + (4000*14)
14400 : 88000
A:B = 18:11.
Answer :
The ratio of their profits A:B = 8:12 = 2:3
Share of A in the total profit = 2/5 * 25000 = Rs.10000 Share of A in the total profit = 3/5 * 25000 = Rs.15000.
Answer :
15:25 => 3:5
9600*10/100 = 960
9600 - 960 = 8640
8640*3/8 = 3240 + 960
= 4200.
Answer :
Ratio of investments of P and Q is 2 : 5
Total salary claimed by P = 12 * 5000 = Rs. 60000
Total profit = Rs. 2 lakhs.
Profit is to be shared = Rs. 140000
Share of P = (2/7) * 140000 = Rs. 400000
Share of Q = Rs. 100000
Total earnings of P = (60000 + 40000) = Rs. 100000
Ratio of their earnings = 1 : 1.
Answer :
The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15
= 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60
Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.
The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k
It is given that A paid Rs. 1125
45k = 1125 => k = 25
246k = 246(25) = Rs. 6150
Thus the total rent paid by all the four agencies is Rs. 6150.
Answer :
Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6
Total profit = Rs. 52000
Share of B = 6/13 (52000) = Rs. 24000.
Answer :
Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6
And also given that, profit share of B is Rs. 1500
=> 5 parts out of 15 parts is Rs. 1500
Now, required difference is 6 - 4 = 2 parts
Required difference = 2/5 (1500) = Rs. 600.
Answer :
Interest received by A from B = 10% of half of Rs.50000 = 10% * 25000 = 2500.
Amount received by A per annum for being a working partner = 1500 * 12 = Rs.18000.
Let 'P' be the part of the remaining profit that A receives as his share. Total income of A = (2500 + 18000 + P)
Total income of B = only his share from the remaining profit = 'P', as A and B share the remaining profit equally.
Income of A = Twice the income of B
(2500 + 18000 + P) = 2(P)
P = 20500
Total profit = 2P + 18000
= 2*20500 + 18000 = 59000.
Answer :
Speed downstream = 24/10 km/hr = 2.4 km/hr
Speed upstream = 24/12 km/hr = 2 km/hr
Speed of the boat in still water = ½ (2.4 +2)km/hr = 2.2 km/hr.
Answer :
Let the distance between the two parts be x km.
Then speed downstream = x/4 km/hr.
Speed Upstream = x/5 km/hr
Speed of the stream = ½ (x/4 –x/5)
Therefore, ½(x/4 –x/5) = 2. => x/4 –x/5 = 4 => x = 80.
Hence, the distance between the two ports is 80km.
Answer :
Speed downstream = (30 x 2/5)km/hr = 12km/hr
Speed upstream = (30 x 4/15) km/hr = 8 km/hr
Speed of boat in still water = ½ (12 + 8)km/hr = 10 km/hr.
Answer :
Let the speed of motor boat be 36x km/hr and that of current of water be 5x km/hr
Speed downstream = (36x +5x)km/hr = 41x km/hr
Speed upstream = (36 -5x)km/hr = 31x km/hr
Distance covered downstream = (41x × 31/6)km
Distance upstream = [1271x/6 × 1/31x]hrs
= 41/6 hrs = 6hrs 50 min.
Answer :
Let the length be x metres and breadth be y metres
Then it’s area =(xy)m2
New length =(125/100 x)m =(5x/4)m.
Let the new breadth be 2 metres
Then xy 5x/4 x 2 => 2 = 4/5 y
Decreased in width =(y -4/5 y) = y/5 metres
Decreased % in width =(y/5 x 1/y x 100)% = 20%.
Answer :
Let length = x metres and breadth = y metres, then area =(xy)
New length =(120/100x)m = 6x/5 m
New breadth =(80/100 y)m
New area =(6x/5 x 4y/5)m2 = (24/25 xy)m2
Decreased in area =(xy – 24/25 xy)m2= xy/25 m2
Decreased % =(xy/25 x 1/xy x 100)% = 4%.
Answer :
Let the breadth be x metres then length = 2x metres
=> 2(2x+x) = 60
=> 6x =60
=> x =10
l = 20m and b =10m
=> Area =(20 x 10) Sq.m = 200 Sq.m.
Answer :
Let the breadth be x metres , then it’s length = 3x metres
=>3x × x =12
=> x2= 4
=> x =2 l=6m, b =2m
=> Perimeter = 2(6+2)m = 16m.
Answer :
Length of the be let ‘l’ units and breadth be b units
Area =lb sq. Units
Now length =(110/100 l) = 11l/10
New breadth =(90/100 b) = 96/10
Now area (11l/10 x 96/10)Sq.units = (99/100 lb)sq.unit
Area decreased = (lb -99/100 lb)sq.units =lb/100 sq.Units
Percentage decreased =(lb/100 x 1/lb x 100)% = 1%.
Question 30. How Many Meters Of Carpet 63cm Will Be Required To Be A Floor Of A Room 14m By 9cm?
Answer :
Width of the carpet = 63/100 m let it’s length be x metres
Then x × 63/100 = 14 x 9
=> x =(14 x 9 x 100/63) = 200m
Length = 200m.
Answer :
Time for one revolution = 60/15 = 4
60/ 20 = 3
60/48 = 5/4
LCM of 4, 3, 5/4
LCM of Numerators/HCF of Denominators =
60/1 = 60.
Answer :
Lowest 4-digit number is 1000.
LCM of 3, 4 and 5 is 60.
Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.
Now, add the remainder 2 that's required. Thus, the answer is 1022.
Answer :
Calculate the differences, taking two numbers at a time as follows:
(215-47) = 168
(365-215) = 150
(365-47) = 318
HCF of 168, 150 and 318 we get 6, which is the greatest number, which while dividing 47, 215 and 365 gives the same.
emainder in each cases is 5.
Answer :
Length = 6 m 24 cm = 624 cm
Width = 4 m 32 cm = 432 cm
HCF of 624 and 432 = 48
Number of square tiles required = (624 * 432)/(48 * 48) = 13 * 9 = 117.
Answer :
The number of liters in each can = HCF of 80, 144 and 368 = 16 liters.
Number of cans of Maaza = 80/16 = 5
Number of cans of Pepsi = 144/16 = 9
Number of cans of Sprite = 368/16 = 23
The total number of cans required = 5 + 9 + 23 = 37 cans.
Answer :
Let the numbers be a and b. Then,
a + b = 12 and ab = 35.
(a + b)/ab = 12/35
= (1/b + 1/a) = 12/35
Sum of reciprocals of given numbers = 12/35.
Question 37. How Many Of The Following Numbers Are Divisible By 132?
Answer :
264, 396, 462, 792, 968, 2178, 5184, 6336
132 = 11 * 3 * 4
Clearly, 968 is not divisible by 3
None of 462 and 2178 is divisible by 4
And, 5284 is not divisible by 11
Each one of the remaining four numbers is divisible by each one of 4, 3 and 11.
So, there are 4 such numbers.
Question 38. Which One Of The Following Numbers Is Exactly Divisible By 11?
Answer :
(4 + 5 + 2) - (1 + 6 + 3) = 1, not divisible by 11.
(2 + 6 + 4) - (4 + 5 + 2) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 3) = 1, not divisible by 11.
(4 + 6 + 1) - (2 + 5 + 4) = 0.
So, 415624 is divisible by 11.
Question 39. 9 3/4 + 7 2/17 - 9 1/15 = ?
Answer :
Given sum = 9 + 3/4 + 7 + 2/17 - (9 + 1/15)
= (9 + 7 - 9) + (3/4 + 2/17 - 1/15)
= 7 + (765 + 120 - 68)/1020 = 7 817/1020.
Question 40. The Surface Area Of A Cube Is 726m2, Its Volume Is?
Answer :
6a2= 726
=> a2 = 121
=> a = 11 Cm
Therefore, Volume of the cube
= (11 × 11 × 11) cm3 = 1331 cm3.
Answer :
Length = 6x
Breadth = 5x
Height = 4x in cm
Therefore, 2(6x × 5x + 5x × 4x + 6x × 4x) = 33300
148x2 = 33300
=> x2 = 33300/148 = 225
=> x = 15.
Therefore, Length = 90cm,
Breadth = 75cm,
Height = 60cm
90, 75 , 60 cm.
Answer :
Let Rajan's present age be x years.
Then, his age at the time of marriage = (x - 8) years.
x = 6/5 (x - 8)
5x = 6x - 48 => x = 48
Rajan's sister's age at the time of his marriage = (x - 8) - 10 = 30 years.
Rajan's sister's present age = (30 + 8) = 38 years.
Answer :
Let the ages of the children be x, (x + 3), (x + 6), (x + 9) and (x +12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20 => x = 4.
Age of youngest child = x = 4 years.
Answer :
Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) = 42 years.
Required difference = (42 - 36) = 6 years.
Answer :
Present ages of son and father be x years (56 -x)years
(56- x +4) = 3(x + 4) or 4x =48 or x = 12
Ages are 12 years, 44 years.
Answer :
Rita’s age 2 years ago be x years
Pushpa’s present age =(2x) years
2x –(x +2) =2 => x =4
Therefore pushpa’s present age = 8 years.
Answer :
Suppose, salary = Rs. 100
Expenditure on food = Rs. 40
Balance = Rs. 60
Expenditure on transport = 1/3 × Rs. 60 = Rs. 20
Now, balance = Rs. 40
Saving = Rs. 20
If saving is = Rs. 20
Salary = Rs. 100
If saving is Rs. 450,
salary = Rs (100/20 x 450) = Rs. 2250.
Answer :
Let original price = Rs. 100.
Reduced Price = Rs. 75.
Increase on Rs. 75 = Rs. 25
Increase on 100 = (25/75 x 100) % = 33 1/3 %.
Answer :
Let length = 100 m.
Breath = 100 m.
New length = 160 m.
New breath = x meters
Then, = 160 × x = 100 × 100
(or) X = (100 ×100)/160 × 125/2
Decrease in breadth = (100- 125/2) % = 37 ½ %.
Answer :
Let tax = Rs. 100 and consumption = 100 units
Original Expenditure = Rs. (100 × 100) = Rs. 10000
New Expenditure = Rs. (120 × 80) = Rs. 9600
Decrease in expenditure = (400/10000 x 100) % = 4 %.
Answer :
Let price = Rs. 100, Sale = 100
Then Sale Value = Rs. (100 × 100) = Rs. 10000
New Sale Value = Rs. (70 × 120) = Rs. 8400
Decrease % = (1000/10000 x 100) % = 16 %.
Answer :
Basic rate per hour = Re. (20/40) = Re. 1/2.
Overtime per hour = 125 % of Re. 1/2 = Re.5/8.
He worked x hours overtime.
Then 20 + 5/8 x = 25 (or) = 5/8 x = 5
X = 40/5 = 8 hours
=> he worked in all for (40 + 8) = 48 hours.
Question 53. If 35% Of A Number Is 12 Less Than 50% Of That Number, Then The Number Is?
Answer :
Let the number be x. Then,
50% of x - 35% of x = 12
50/100 x - 35/100 x = 12
x = (12 * 100)/15 = 80.
Answer :
Let the price of the article = Rs.100
New price = 100 - 10 = 90
Therefore the new price must be increased by(100−90)×100/90=100/9%=11 1/9%.
Answer :
Let the business value changes from x to y.
Then 4 % of x = 5 % of y of 4/100 × x = 5/100 × y
or y = 4/5 x.
Change in business = (x - 4/5 x) = 4/5 x.
Percentage slump in business
= (1/5 x ×1/x × 100)% = 20%.
Question 56. If 20% Of A Number, Then 120% Of That Number Will Be?
Answer :
Let the number x. Then,
20% of x = 120
x = (120 * 100)/20 = 600
120% of x = (120/100 * 600) = 720.
Question 57. Two-fifth Of One-third Of Three-seventh Of A Number Is 15. What Is 40% Of That Number?
Answer :
Let the number be x. Then,
2/5 of 1/3 of 3/7 of
x = 15 => x = (15 * 5/3 * 3 * 5/2) = 525/2
40% of 525/2 = (40/100 * 525/2) = 105.
Question 58. The Difference Between A Number And Its Two-fifth Is 510. What Is 10% Of That Number?
Answer :
Let the number be x. Then,
x - 2/5 x = 510
x = (510 * 5)/3 = 850
10% of 850 = 85.
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